Answer:
The magnitude of the electric flux is [tex]3.53\ N-m^2/C[/tex]
Explanation:
Given that,
Electric field = 2.35 V/m
Angle = 25.0°
Area [tex]A= 1.65 m^2[/tex]
We need to calculate the flux
Using formula of the magnetic flux
[tex]\phi=E\cdot A[/tex]
[tex]\phi = EA\cos\theta[/tex]
Where,
A = area
E = electric field
Put the value into the formula
[tex]\phi=2.35\times1.65\times\cos 25^{\circ}[/tex]
[tex]\phi=2.35\times1.65\times0.91[/tex]
[tex]\phi=3.53\ N-m^2/C[/tex]
Hence, The magnitude of the electric flux is [tex]3.53\ N-m^2/C[/tex]
