Given:
[tex]s=-\frac{5\pi}{3}[/tex]
To find the point (x,y) on the unit circle:
The coordinate of the unit circle can be derived by,
[tex](\cos s,\sin s)[/tex]
Substituting the value of s, we get
[tex]\begin{gathered} (\cos (-\frac{5\pi}{3}),\sin (-\frac{5\pi}{3}))=(\cos (2\pi-\frac{5\pi}{3}),\sin (2\pi-\frac{5\pi}{3})) \\ =(\cos (\frac{\pi}{3}),\sin (\frac{\pi}{3})) \\ =(\frac{1}{2},\frac{\sqrt[]{3}}{2}) \end{gathered}[/tex]
Hence, the coordinate point on the unit circle is,
[tex](\frac{1}{2},\frac{\sqrt[]{3}}{2})[/tex]
